written 8.3 years ago by | • modified 4.5 years ago |
Steady, incompressible flow consist of following velocity components:
$u=\dfrac{cx}{y} \\ v=c \bullet ln(xy)$
Obtain a relevant stream function for the fluid flow.
written 8.3 years ago by | • modified 4.5 years ago |
Steady, incompressible flow consist of following velocity components:
$u=\dfrac{cx}{y} \\ v=c \bullet ln(xy)$
Obtain a relevant stream function for the fluid flow.
written 8.3 years ago by |
Given that the above velocity components represent a Steady and Incompressible flow,
$u=\dfrac{cx}{y} \\ v=c∙ln(xy)$
We know that the relation between the stream function and the velocity functions are as follows,
$u=\dfrac{∂ψ}{∂y} \\ v=-\dfrac{∂ψ}{∂x}$
Now,
$\dfrac{∂ψ}{∂y}=\dfrac{cx}{y}$
Integrating with respect to y treating x as a constant,
$ψ=cx∙ln(y)+fn(x).............. (1)$
Also,
$\dfrac{∂ψ}{∂x}=-c∙ln(xy)$
Integrating with respect to x treating y as a constant,
$ψ=∫-c∙ln(xy)dx \\ ψ=∫-c∙[ln(x)+ln(y)]dx \\ ψ=-c\{∫ln(x)dx+x∙ln(y)\}+fn(y)$
Using Integration by parts,
$$ψ=-c \bigg\{ln(x)∙x-∫ \dfrac 1x x dx+x∙ln(y)\bigg\}+fn(y)$$
$ψ=-c\bigg\{ln(x)∙x-x+x∙ln(y)\bigg\}+fn(y) \hspace{1cm}\bigg\{∵∫uv dx=u∫v dx-∫\bigg[\dfrac{du}{dx} ∫v dx \bigg]\bigg\} \\ ψ=-cx \{ln(x)+ln(y)-1 \}+fn(y).........… (2)$
Comparing equation (1) and (2)
$ψ=cx\{1-ln(xy)\}$
…this is the required stream function.