Calculate the thermal noise power available from any resistor at a temperature of 290 K for a bandwidth of 1 MHz. Calculate also the corresponding noise voltage if the resistance R = 100 $\Omega$

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Calculate the thermal noise power available from any resistor at a temperature of 290 K for a bandwidth of 1 MHz. Calculate also the corresponding noise voltage if the resistance R = 100

$\Omega$

written 8.7 years ago by

teamques10 ★ 69k

modified 3.1 years ago by

sagarkolekar ★ 11k

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written 8.7 years ago by

teamques10 ★ 69k

Given Data:

Temperature, T = 290 K

Bandwidth, B = 1 MHz

R = 100 Ω

To find:

Thermal noise power, $P_N$ =?

Noise voltage, $V_N$ =?

Solution:

Thermal noise power is given as:

$P_N$ = k T B

$= 1.38 \times 10^{-23} \times 290 \times 1 \times 10^6 \\ = 4.003 …

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