0
23kviews
Evaluate $\int \frac{sin\pi z^2 + cos\pi z^2}{(z - 1)(z - 2)}dz$, where c is the circle $|z| = 3$
1 Answer
written 8.3 years ago by |
The circle $|z| = 3$ has center at (0, 0) and radius 3. The point z = 1 and z = 2 lie inside the circle. Hence f(z) is analytic in C. Hence using partial fraction by removing
$f(z) = sin\pi z^2 + cos\pi z^2$
$\frac{1}{(z - 1)(z - 2)} …