0
1.5kviews
With the help of neat circuit diagram and pharos diagram explain the2-wattmeter method to measure power in a 3-phase balanced delta connected load.
1 Answer
0
6views
written 8.3 years ago by |
i) Assumptions:-
a) The 3-ø system consider here is a load, which is delta connected.
b) The phase sequence is R→Y→B.
c) It is balanced load.
d) The p.f. of each phase is logging.
ii) Connection:-
iii) Proof:-
Reading of wattmeter W1
$W_1=V_{RB}I_{RL} \cos(\angle between V_{RB} \& I_{RL})=V_LI_L \cos(30^0-\emptyset_{ph})$
Reading diagram W2
$W_1=V_{YB}I_{YL} \cos(\angle between V_{YB} \& I_{YL})=V_LI_L \cos(30^0+\emptyset_{ph})$
$(W_1+W_2)=V_LI_L\{\cos(30^0-\emptyset_{ph})+\cos(30^0+\emptyset_{ph})\} \\ =V_LI_L\{2\cos30^0.\cos\emptyset_{ph}\} \\ =V_LI_L\bigg\{2\times\dfrac{\sqrt3}{2}\cos\emptyset_{ph}\bigg\} \\ =\sqrt3V_LI_L \cos \emptyset_{ph} \\ =\text{Total power consumed by the 3-}\emptyset \text{load phasor diagram on}P_011$
ADD COMMENT
EDIT
Please log in to add an answer.