written 8.3 years ago by
teamques10
★ 68k
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•
modified 8.3 years ago
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Given
$P_{ACTIVE}=18kw, \\ \;
\cos \emptyset=0.866 \\ \;
V_L=400V$
In Star connection
$e_{ph}=\dfrac{V_L}{\sqrt3}=230.94 V \\ \;
P_{ACTIVE}=\sqrt3V_LI_L \cos \emptyset$
$I_L$ $=\dfrac{18\times1000}{\sqrt3\times400\times0.866} \\ \;
=\dfrac{180}{6} \\ \;
=30A$
$\cos \emptyset=\dfrac RZ= \gt R=Z \cos \emptyset=6.666\Omega \\ \;
X_L=\sqrt{Z^2-R^2}=3.85\Omega \\ \;
L=\dfrac{X_L}{2\pi f}=\dfrac{3.85}{100 \times \pi}=0.01226 H \\ \;
R=6.666 \Omega \\ \;
L=0.01226 H$
$V_{ph}=230.94 V \\ \;
I_{ph}=30 A$
$V_L=400V \\ \;
\emptyset=30^0$
$\hspace{2cm}$ $Scale:-for100V=1cm \\ \;
\text{for current}10A=1cm$