Given:

$Rpn = 15 Ω Ipn= 0.03 H \\ \text{For star connected load} \\ VL= 400 V, f= 50 Hz \\ \text{Phase and Line current} \\ XLpn= 2 * π * 50 * 0.03 \\ = 9.42 Ω \\ ∴ \text{Zph= Rpn * jXLpn} \\ = (15 + j 9.42) Ω \\ = 17.72 \lt 32.13o Ω \\ ∴ Ipn = IL = Vph / Zph = VL/ \sqrt3 ph \\ = 400/ \sqrt3 * 17.72 \\ \text{Total power absorbed} \\ P= \sqrt3 VL IL \cos ф \\ = \sqrt3 * 400 * 13.03 * \cos (32.13) \\ \therefore PT = 7646.44 W \\ \text{Delta connected load} \\ \text{Phase current Iph = Vph/ Zph} \\ = VL/ Zph = 400/ 17.72 = 22.57 A \\ \text{Line current IL} \\ IL= \sqrt3 Iph \\ = \sqrt3 * 22.57 \\ = 39.09 A \\ \text{Total power absorbed} \\ P = \sqrt3 VLIL \cos ф \\ = \sqrt3 * 400 * 39.09 * \cos (32.13^o) \\ PT = 22939.33 W$