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In a balanced three phase circuit, power is measured by two watt meter readings is 2:1. Determine the power factor of the system.

written 8.3 years ago by teamques10 ★ 68k

•   modified 4.6 years ago

basic electrical engineering

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written 8.3 years ago by teamques10 ★ 68k

→ Given W1/ W2 = 2/1

Therefore W1 = 2W2

Tan Ф = √3 W1- W2/ W1 + W2

= √3 W2/3W2 = √3 (1/3) = 0.577

∴ tan Ф = 0.577

Ф = tan -1 (0.577)

= 30o

Pf= cos Ф = cos (30o) = 0.866 (lagging)

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