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In a phase power measurement try two watt meter method both the watt meter read the same value. What is the power factor of the load? Justify your answer.

written 8.3 years ago by teamques10 ★ 68k

•   modified 4.6 years ago

basic electrical engineering

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written 8.3 years ago by teamques10 ★ 68k

•   modified 8.3 years ago

$\text{Given that W1 = W2} \\ \text{∴ Power factors are equal. } \\ \tan ф = \sqrt3 W1 – W2/ W1 + W2 \\ = \sqrt3 W1- W1/ W1 + W1 \\ = \sqrt3 (0) \\ = 0 \\ ∴ \tan ф = 0 \\ ф = 0 \\ \text{Power factor}= \cos ф = \cos (00) = 1 \\ \text{The power factors of two equal way meters will be unity.}$

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