Mumbai University > FE > Sem 1 > Basic Electrical and Electronics Engineering

Marks: 4 M

Year: Dec 2013

Circuit diagram:

Current:

The alternating current “i” is given by,

i $=C \dfrac{dv}{dt} \\ =C \dfrac{d}{dt}(V_m \sin⁡ωt) \\ =ωCV_m \cos⁡ωt \\ =ωCV_m \sin⁡(ωt+90^0) \\ =I_m \sin⁡(ωt+90^0 )………….(I_m= ωCV_m )$

Here the current leads voltage by 90°

Waveforms:

Phasor diagram:

$Z= \dfrac VI= \dfrac{V_m}{I_m} = \dfrac{V_m}{ωCV_m}= \dfrac{1}{ωC} …