The reverberation time is found to be 1.5 second for an empty Hall and it is 5 found to be 1.0 second when a curtain cloth of 20m* is suspended at the centre of the Hall. If the dimensions of the hall are 10 × 8 × 6m*' - Mumbai university > FE > SEM 1 > Applied Physics 1

Marks: 5M

Year: May 2015

Given:

T1 = 1.5 sec

T2 = 1sec

L = 20m

V = 10 × 8 × 6

To find: $α’ = \frac{0.161V}{2S}[\frac{1}{T_2} - \frac{1}{T_1}]$

$=\frac{0.161V}{2S}[\frac{1}{1} - \frac{1}{1.5}]$

$= 0.103 ( 1 - 0.667 )$

$α' = 0.0343$