using the domain theory and with help of a graph. A magnetic field of 1800amp/m produces a magnetic flux of $3 × 10^{-4}$ Wb in an iron bar of cross sectional area 0.2 cm . -

Mumbai university > FE > SEM 1 > Applied Physics 1

Marks: 8M

Year: Dec 2014

Given:

H = 1800 mho/m

$Φ = 3 ×10^-4Wb$

$A = 0.2cm^2$

To find: ψ = ? μ =?

Soln:

$Φ = B × A$

$B=\frac{Φ}{A} =\frac{3 × 10^{-4}}{0.2 × 10^{-4}} =15Wb/m^2$

$B = µo (H + M)$

$15 = 4π × 10^{-7}(1800 + M)$

$M = 1.194 × 10^7-1800$

$M =11941200Wb/m$

$ψ = \frac{M}{H}=\frac{11941200}{1800}=6634$