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A ball of mass 'm' hits directly to a similar ball of mass 'm' which is at rest. The velocity of first ball after impact is zero. Half of the initial kinetic energy is lost in impact

Find coefficient of restitution

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Let A & B be two balls

$UA=u , VA=0\space\space \&\space\space UB=0 , VB=v $

Applying coefficient of restitution eqn,

$e = - (VB - VA)/( uB - uA) = - (v) /(-u) = v/u\text {____(i)} $

Now, initial kinetic energy $= (1/2)mu2 $

Final kinetic energy $= (1/2)mv2 $

But as half the kinetic energy is lost, initial KE= 2* final KE

$(1/2)mu2 = 2* (1/2)mv2 \\ v/u = 1/\sqrt2\text {_____(ii) } $

from (i) & (ii)

$e = 1/\sqrt2 = 0.707 $

Coefficient of restitution is $0.707 $

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