0
423views
Prove, $(\mathrm{AVB}) \wedge[(\neg \mathrm{A}) \wedge(\neg \mathrm{B})]$ is a contradiction.
1 Answer
0
14views

Solution:

$ \text { To Prove:- }(A \vee B) \wedge[(\neg A) \wedge(\neg B)] \text { is a contradiction. }\\ $

$ \begin{array}{|c|c|c|c|c|c|c|} \hline A & B & A \vee B & \neg A & \neg B & (\neg A) \wedge(\neg B) & (A \vee B) \wedge[(\neg A) \wedge(\neg B)] \\\\ …

Create a free account to keep reading this post.

and 3 others joined a min ago.

Please log in to add an answer.