This configuration is a emitter unbypassed configuration

The input impedance is given by the formula

$Z_{i} = R_{B}||Z_{b}$

$Z_{b} = \beta R_{E}$

$\beta_{re}=6800$

$r_{e}$=$\dfrac{6800}{140}=38.5,$

From the figure it is clear that Emitter resistance is zero

$R_{E}$=0;

$Z_{i}$=120+68=188$K\Omega$

The output impedance of bypassed emitter  resistance BJT transistor is given by 

$Z_{o}=R_{c}$ …