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Find Centroid of shaded area with reference to X and Y axes.
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Part $A_i \ \ \ (cm^2)$ $x_i\ \ \ (cm)$ $y_i \ \ \ (cm)$ $A_ix_i\ \ (cm^3)$ $A_iy_i\ \ (cm^3)$
Square ABCD $20\times 20=400\ \ cm^2$ $=\dfrac{20}{2}=10\ cm$ $=\dfrac{20}{2}=10\ cm$ 4000 4000
Quarter Circle $-100\pi $ $\dfrac{4\times R}{3\pi }=\dfrac{4\times20}{3\pi }=8.488cm$ $R-\dfrac{4\times R}{3\pi }=20-\dfrac{4\times 20}{3\pi }=11.512 \ cm$ -2666.58 -3616.60 …

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