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Draw shear force and bending moment for simply supported beam

Figure is shown below

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Reaction Calculation:

$$ \begin{array}{l}{\begin{aligned} \sum \mathrm{M}_{\mathrm{A}} &=0 \\ \mathrm{R}_{\mathrm{B}} \times 5.5 &=(2 \times 2) \times 1+1.5 \times 2+30 \\ \mathrm{R}_{\mathrm{B}} &=6.72 \mathrm{kN} \\ \Sigma \mathrm{Fy}=& 0 \end{aligned}} \\ {\mathrm{R}_{\mathrm{A}_{\mathrm{A}}}+\mathrm{R}_{\mathrm{B}}=(2 \times 2)+1.5} \\ {\mathrm{R}_{\mathrm{A}}=-1.22 \mathrm{kN}}\end{array} $$

2) SF Calculation:

$$ \begin{array}{l}{\text { SF at } A=-1.22 \mathrm{kN}} \\ {\mathrm{C}_{\mathrm{L}}=-1.22-(2 \times 2)=-5.22 …

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