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A timber beam 100 mm wide and 150 mm deep supports a2 UDL over a span of 2 m, if the safe stresses are 28 N/mm in bending and 2 N/mm2 in shear. Calculate the maximum UDL which can be supported by beam
written 4.7 years ago by gravatar for teamques10 teamques10 ★ 65k modified 2.0 years ago by gravatar for RakeshBhuse RakeshBhuse • 3.2k
strength of materials
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written 4.7 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 2.4 years ago

Given:

For rectangular S.S. beam, b = 100 mm. L = 4m, $\sigma_{b} = 40 N /mm^{2} , q_{max} = 80N/mm^{2}$

Solution:

Max B.M = M = $\frac{wl^{2}}{8} \times 10^{6} Nm$

Max S.F = S = $R_{A} = \frac{wL}{2} \times 10^{3}N$

$For beam section, I = \frac{bd^{3}}{12} = \frac{100 \times …

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