A simply supported beam of 4 m length carries two point loads of 5 kN and 7 kN at 1.5 m and 3.5 m from the left hand support respectively. Draw SFD and BMD.

6.2kviews

written 4.7 years ago by

teamques10 ★ 65k

modified 2.0 years ago by

RakeshBhuse • 3.2k

strength of materials

ADD COMMENT EDIT

1 Answer

744views

written 4.7 years ago by

teamques10 ★ 65k

Reactions:

$\Sigma M_{A} = 0 +ve$

5 x 1.5 + 7 x 3.5 - $R_{B} \times 4 = 0$

$R_{B} = 8kN$

$\Sigma F_{y} +ve,$

$R_{A} + R_{B} - 5 - 7= 0$

$R_{A} = 12 - 8 = 4kN$

enter image description here

S.F. Calculations +ve

$S.F_{A} = 4kN$

$S.F_{C} (left) = 4kN$ …

Create a free account to keep reading this post.

and 4 others joined a min ago.

ADD COMMENT EDIT

Please log in to add an answer.