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A siphon of diameter 200mm connects two reservoirs having a difference in elevation of 15m. The total length of siphon is 600 m and the summit is 4 m above the water level in the upper reservoir.

If the separation takes place at 2.8 m of water absolute, find the maximum length of siphon from the upper reservoir to summit. Take f'(friction coefficient)=0.004 and atmospheric pressure = 10.3 m of water.

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Solution :

Diagram

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Given :

1) $ d=200 \mathrm{~mm}=0.2 \mathrm{~m}$

2) length of Siphon $=600 \mathrm{~m}$

3) Friction factor $(f)=0.016$

4) Accelerdion due to gravity $(g)=9.81\mathrm{~m} / \mathrm{s}^{2}$

5) $P_{1}=P_{3}=10.3$ m atm of water

6) $P_{2}=2.8 \mathrm{~m}$ of water absolute pressure

7) $ v = \rho g=$ constant

Required formulae …

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