and 5 others joined a min ago.
0
40kviews
Show that G=[1,-1,i,-i] is a group under usual multiplication of complex number.
written 5.4 years ago by
teamques10
★ 65k
|
modified 4.1 years ago
by
prashantsaini
• 0
|
ADD COMMENT
EDIT
1 Answer
0
8.6kviews
|
written 5.4 years ago by
teamques10
★ 65k
|
The adjoioning table shows the result of multiplication of elements G
Since for every pair a,b,E, G
$\ G_1 \Rightarrow$ Since multiplication of complex number is associative, the multiplication associative in G
$\ G_2 \Rightarrow$ From the first coloumn (or row), we see that l is an identity element. Hence, …
ADD COMMENT
EDIT
Please log in to add an answer.