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$\oint \frac{e^{2z}}{(Z+1)^4}dz$ where c is the circle |z-1|=3.
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written 6.3 years ago by
teamques10
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• modified 6.1 years ago |
The path of integration is the circle with centre (1, 0) & radius =3
The points at which the function is not analytic are z= -1 which lies inside C .
By Cauchy’s Integral formula, value of the integral is given by
$∮ \frac{e^{2z}}{(z+1)^4} \ dz$
= $ \frac{2πi}{3!} [\frac{d^3}{dz^3} …
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