Shaft power = 12000 KW, head = 350 m, speed =750 rpm, overall eficiency = 86 %, jet diameter is not to exceed one sixth of the wheel diameter. Determine

(i) Wheel diameter

(ii) Number of jets required

(iii) Diameter of jet

Take coefficient of velocity is 0.985 and speed ratio 0.45

Given

Shaft power S.P= 12000 KW

head H = 350 m

speed N =750 rpm

overall eficiency %= 86 % or 0.86

Ratio of jet dia to wheel dia $\dfrac dD =\dfrac 16$

Coefficient of velocity $K_{v1}=C_v=0.985 $

Speed ratio $K_{u1} = 0.45 $

Velocity of jet = $V_1 = …