written 7.2 years ago by
sumitvalse
• 250
|
modified 2.3 years ago
by
pedsangini276
• 4.8k
|
find the dimension of shorter side of duct.
Mumbai University > Mechanical Engineering > Sem 8 > Refrigeration and air conditioning
Marks: 06M
Year: Dec 2016
written 5.3 years ago by
shaikhrehan227
• 410
|
The given data is
$\frac{b}{a}=7 and \frac{b}{D}=2.6$
For the given condition, the relation between the two geometric sections is given by
D=1.256$[\frac{ab{^3}}{(a+b)}]^{(1/5)}$
substituting the given values
10=$1.265[\frac{(a×7a)^3}{8a}]^{(1/5)}=1.265×a(\frac{343}{8})^{0.2}=2.68a$
∴a=10/2.68=3.73 cm
b=7×3.73=26.12 cm
as $ \frac{b}{D}=\frac{26.2}{10}$=2.61 which satisfes the third given condition
written 2.5 years ago by
Sharad
• 130
|
The given data is
$\frac{b}{a}=7 and \frac{b}{D}=2.6$
For the given condition, the relation between the two geometric sections is given by
D=1.256$[\frac{ab{^3}}{(a+b)}]^{(1/5)}$
substituting the given values
10=$1.265[\frac{(a×7a)^3}{8a}]^{(1/5)}=1.265×a(\frac{343}{8})^{0.2}=2.68a$
∴a=10/2.68=3.73 cm
b=7×3.73=26.12 cm
as $ \frac{b}{D}=\frac{26.2}{10}$=2.61 which satisfes the third given condition
|
written 2.5 years ago by
Sharad
• 130
|
The given data is
$\frac{b}{a}=7 and \frac{b}{D}=2.6$
For the given condition, the relation between the two geometric sections is given by
D=1.256$[\frac{ab{^3}}{(a+b)}]^{(1/5)}$
substituting the given values
10=$1.265[\frac{(a×7a)^3}{8a}]^{(1/5)}=1.265×a(\frac{343}{8})^{0.2}=2.68a$
∴a=10/2.68=3.73 cm
b=7×3.73=26.12 cm
as $ \frac{b}{D}=\frac{26.2}{10}$=2.61 which satisfes the third given condition
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