Mumbai University > Electronics and Telecommunication Engineering > Sem 3 > Digital Electronics

Marks: 5M

Year: May 2016

i) Conversion to BCD:

The hexadecimal number is $(AB)_{16}$

First convert it into decimal number: $(AB)_{16}$ = $10 \times {16^1}$ + $11 \times {16^0}$ $ = 160 + 11 = 171 = {(171)_{10}}$

BCD code for ${(171)_{10}}$ is 0001 0111 0001

Combine all binary bits by removing spaces, 000101110001

Hence …