Arranging the above equation in time constant form,

G(S)H(S)=$\frac{242 x 5 (1+S/5)}{S(1+S)(1+\frac{5}{121} S+S^{2}\frac{1}{121} 121}$

=$\frac{10(1+S/5)}{S(1+S)(1+0.041S+S^2\frac{1}{121})}$

System consists of quadratic pole

Comparing the denominator $(S^2+5S+121)$ with the denominator of standard equation

$S^2+2ξw_nS+w_n^2,$

$w_n^2$=121

$w_n$=11 rad/sec

$2ξw_n$=5

ξ=$\frac{5}{(2 x 11)}$

ξ=0.2

The factors are:

Constant k=10

1 pole at the origin, $\frac{1}{S}$, …